Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Polynomials

Short Answer Type

91. Find the remainder obtained when x⁴ + 3x³ - 2x² + x + 1 is divided by x - 1.

158 Views

92. Check whether the polynomial q(t) = 4t³ + 4t² - t -1 is a multiple of 2t + 1.

190 Views

93. If the polynomial p(x) = x⁴- 2x³ + 3x² - ax + 8 is divided by (x - 2), it leaves a remainder 10. Find the value of a.

122 Views

94. The polynomials x³ + 2x² - 5ax - 8 and x³ + ax² - 12x - 6 when divided by (x - 2), and (x - 3) leave remainder p and q respectively. If q - p =10. find the value of a.

191 Views

95. The polynomials kx³ + 3x² - 8 and 3x³ - 5x + 8 are divided by x + 2. If the remainder in each case in the same, find the value of k.

Solution not provided.

Ans. $5 over 4$

161 Views

96. If f(x) = x⁴- 2x³ + 3x² - ax + b is divided by (x - 1) and (x + 1), it leaves the remainder 5 and 19 respectively. Find ‘a’ and ‘b’.

257 Views

97. Find the remainders when 3x³- 4x² + 7x - 5 is divided by (x - 3) and (x + 3).

143 Views

98. If p(x) =x³ - ax² + bx + 3 leaves a rer.idinder -19 when divided by (x + 2) and a remainder 17 when divided by (x - 2), prove that a + b = 6.

129 Views

99. If remainder is same when polynomial p(x) = x³ + 8x² + 17x + ax is divided by (x + 2) and (x + 1), find the value of a.

192 Views

100. The polynomials ax³ + 3x² - 13 and 2x³ - 5x + a are divided by x - 2. The remainder in each case is the same. Find the value of a.

304 Views

Previous Year Papers

Test Series

Test Yourself

Short Answer Type

95. The polynomials kx3 + 3x2 - 8 and 3x3 - 5x + 8 are divided by x + 2. If the remainder in each case in the same, find the value of k.

95. The polynomials kx³ + 3x² - 8 and 3x³ - 5x + 8 are divided by x + 2. If the remainder in each case in the same, find the value of k.