p(x) = 2x3 + x2 - 2x - 1, g(x) = x + 1g(x) = 0⇒ x + 1 = 0 ⇒ x = - 1∴ Zero of g(x) is - 1.Now, p(- 1)= 2(- 1)3 + (- 1)2 - 2(- 1) - 1= - 2 + 1 + 2 - 1 = 0∴ By factor theorem, g(x) is a factor of p(x).