(2x + 1)3(2x + 1)3 = (2x)3 + (1)3 + 3(2x)(1)(2x + 1)| Using Identity VI= 8x3 + 1 + 6x(2x + 1)= 8x3 + 1 + 12x2 + 6x= 8x3+ 12x2 + 6x + 1