Number of red balls in the bag = 5 Let number of blue balls in the bag = x Total number of balls in the bag = x + 5 i.e., n(S) = x + 5
Let A be the favourable outcomes of getting red balls, then
n(A) = 5
Therefore, P(A) =
Let B be the favourable outcomes of getting blue balls, then
n(B) = x
Therefore, P(B) =
According to equation, P(B) = 2 P(A)
Hence, the number of blue balls in the bag is 10.
A box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball? If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.