A box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball? If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.
i.e., n(S) = 12
(0 Let A be the favourable outcomes of getting black ball, then
n(A) = x
Therefore,
P(A) =
(ii) Number of white balls in the box = x + 6 Total number of balls in the box = 12 + 6 = 18. i.e., n(S) = 18
Let B be the favourable outcomes of getting new white balls, then
n(B) = x + 6
Therefore,
P(B) =
Now according to question
P(B) = 2P(A)
Hence, the number of white balls = 3.