A jar contains 24 marbles, some are green and others are blue. I

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 Multiple Choice QuestionsFill In the Blanks

131. The probability of an event that cannot happen is ________ Such an event is called __________.
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132. The probability of an event that is certain to happen is ________ Such an event is called _________.
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133. The sum of the probabilities of all the elemen-tary events of an experiment is ______.
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 Multiple Choice QuestionsShort Answer Type

134. Which of the following arguments are correct and which are not correct ? Give reasons for your answer.

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135. Two customers Shyam and Ekta are visiting a particular shop in the same weak (Tuesday to Saturday). Each is equally likely to visit the shop on any day as on another day. What is the probability that both will visit the shop on (i) the same day? (ii) consecutive days? (iii) different days?
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136. A die is a numbered in such a way that its face show the numbers 1, 2, 2, 3, 3, 6. It is thrown two times and the total score in two throws is noted. Complete the following table which gives a few values of the total score on the two throws :


What is the probability that the total scene is (i) even, (ii) 6, (iii) at least 6.
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137. A bag contains 5 red balls and some blue balls. If the probability of drawing a blue ball is double that of red ball, find the number of blue balls in the bag.
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138.

A box contains 12 balls out of which x are black. If one ball is drawn at random from the box, what is the probability that it will be a black ball? If 6 more black balls are put in the box, the probability of drawing a black ball is now double of what it was before. Find x.

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139. A jar contains 24 marbles, some are green and others are blue. If a marble is drawn at random from the jar, the probability that it is green is 2 over 3 Find the number of blue balls in the jar.


Total number of marbles in the jar = 24
i.e.    n(S) = 24
Let number of blue balls in the jar be x.
Then, the number of green balls in the jar = 24 – x Let A be the favourable outcomes of getting blue balls. Then
n(A) = x

Therefore, P(A) = fraction numerator straight n left parenthesis straight A right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals x over 24

Let B be favourable outcomes of getting green balls. Then
n(B) = 24 – x

Therefore,  P(B) = fraction numerator straight n left parenthesis straight B right parenthesis over denominator straight n left parenthesis straight S right parenthesis end fraction equals fraction numerator 24 minus x over denominator 24 end fraction
According to the given condition :

                P(B) = 2 over 3

rightwards double arrow space space space space space space space space fraction numerator 24 minus straight x over denominator 24 end fraction equals 2 over 3
rightwards double arrow space space space space space space space space 3 left parenthesis 24 minus straight x right parenthesis space equals space 2 space straight x space 24
rightwards double arrow space space space space space space space space 72 minus 3 straight x equals 48
rightwards double arrow space space space space space space space space minus 3 straight x space equals space 48 minus 72
rightwards double arrow space space space space space space space space plus 3 straight x space equals space minus 24
rightwards double arrow space space space space space space space space space space space space straight x space equals space 8 space
Hence, the number of blue balls in the jar = 8.

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140. A box contains cards marked with numbers 5 to 20. A card is drawn from the bag at random. Find the probability of getting a number which is a perfect square.
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