Total no. of possible outcome(s) are 18. i.e., n(S) =18
Let A be the favourable outcomes of getting the number on the card which is an even number, then
A = (4,6,8,10,12,14,16,18,20) i.e., m(A) = 9
Therefore,
P(A) =
A die thrown once. Find the probability of getting
(i) an even prime number
(ii) a multiple of 3