Short Answer TypeIf we toss a coin then we get either a head or a tail. Thus number of possible outcomes(s) are two–Head(H) and Tail(T).
i.e., S = |HT|
⇒ n(S) = 2
Let E be the favourable outcomes of getting head, then
E = {H}
⇒ n(E) = 1
Therefore, P(E) P(Head) = 
Let F is the favourable outcomes of getting Tail, then
F = {T}
⇒ n(F) = 1
Therefore, P(F) = P(Tail) = 
Note : For any event E, P(E) + P(Ē) = 1.
Where Ē stands for‘note’E and Ē are called complementary favourable events.
Two coins are tossed simultaneously. Find the probability of getting.
(i) two heads, (ii) at least one head, (iii) no head.
A die is thrown once. Find the probability of getting
(i) an even number.
(ii) a number greater than 3.
(iii) a number between 3 and 6.
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