Short Answer TypeA box contains 5 red balls, 4 green balls and 7 white balls. A ball is drawn at random from the box. Find the probability that the ball drawn is
(a) White (b) neither red nor white
(i) white ball or a green ball.
(ii) neither a green ball not a red ball.
Total number of balls in the bag = 5 + 8 + 7 = 20
i.e. n( S) = 20
(i) Let A be the favourable outcomes of getting a white ball or a green ball. Then n( A) = 15
Therefore,
P(getting a white ball or a green ball)
(ii) Let B be the favourable outcomes of getting neither of a green ball nor a red ball. Then h(B) = 7
Therefore, P(getting neither a green ball nor a red ball)
Cards marked with the numbers 2 to 101 are placed in a box and mixed throughly. One card is drawn from this box. Find the probability that the number on the cards is
(i) an even number
(ii) a number less than 14.
(iii) a number which is a perfect square.
(iv) a prime n umber less than 20.
18 Cards, numbered 1, 2, 3, ..., 18 are put in a box and mixed throughly. A card is drawn at random from the box. Find the probability that the Card drawn bears
(i) an even number
(ii) a number divisible by 2 or 3
12 cards, numbered 1, 2,3......., 12 are put in a box and mixed throughly. A card is drawn at random from the box. Find the probability that the card drawn bears
(i) an even number
(ii) a number divisible by 2 or 3.
Switch
