If A, B, C are any three events, then prove that

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(B ∩ C) - P(C ∩ A) + P(A ∩ B ∩ C)

603. Which of the following cannot be valid assignment of probabilities for outcomes of sample space: S = {ω₁, ω₂, ω₃, ω₄, ω₅, ω₆, ω₇}
Assignment:
                                                       

(a)   0.1       0.01       0.05        0.03      0.01      0.2           0.6

(b)                                                        

(c)    0.1        0.2        0.3          0.4        0.5        0.6          0.7

(d)    -0.1      0.2         0.3          0.4       -0.2       0.1          0.3

(e)