If A, B, C are any three events, then prove that
P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B) - P(B ∩ C) - P(C ∩ A) + P(A ∩ B ∩ C)
A die is rolled twice.
Sample Space, S = n(S) = n = 36
Event A: Getting a doublet. E = {(1,1), (2,2), (3,3), (4,4), (5,5), (6,6)}
n(A) = m = 6
∴