X |
0 |
1 |
2 |
P(X) |
0.4 |
0.4 |
|
X |
0 |
1 |
2 |
3 |
4 |
P(X) |
0.1 |
0.5 |
0.2 |
-0.1 |
0.3 |
X |
0 |
1 |
2 |
3 |
4 |
P(X) |
0.1 |
0.5 |
0.2 |
-0.1 |
0.3 |
Here P(X) = -0.1 for X = 3
This is not possible as 0 ≤ P(X) ≤ 1
∴ given distribution is not a probability distribution of a random variable
Y |
-1 |
0 |
1 |
P(Y) |
0.6 |
0.1 |
0.2 |
Z |
3 |
2 |
1 |
0 |
-1 |
P(Z) |
0.3 |
0.2 |
0.4 |
0.1 |
0.05 |
(a) Find the value of k.
(b). What is the probability that you study at least two hours ? Exactly two hours ? At most two hours?
X |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
1 |
P(X) |
0 |
k |
2k |
2k |
3k |
k2 |
2k2 |
7k2 + k |
(a) Determine the value of k.
(b) Find P(X < 2), P(X ≤ 2), P(X ≥ 2).