Three cards are drawn successively with replacement from a well-

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 Multiple Choice QuestionsShort Answer Type

961. An urn contains 3 white and 4 red balls. 3 balls are drawn one by one with replacement. Find the probability distribution of the number of red balls.
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962. Find the probability distribution of green balls drawn when 3 balls are drawn one by one without replacement from a bag containing 3 green and 5 white balls.
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963. Find the probability distribution of white balls drawn when 3 balls are drawn one by one without replacement from a bag containing 4 white and 6 red balls.
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964. A bag contains 2 white, 3 red and 4 blue balls. Two balls are drawn at random from the bag. If the random variable X denotes the number of white balls among the two balls drawn, describe the probability distribution of X.
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 Multiple Choice QuestionsLong Answer Type

965. Two bad eggs are mixed accidentally with 10 good one. Find the probability distribution of the number of bad eggs in 3, drawn at random, from this lot.
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966. From a lot of 30 bulbs which include 6 defectives, a sample of 4 bulbs is drawn at random with replacement. Find the probability distribution of the number of defective bulbs.
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967. Find the probability distribution of number of doublets in three throws of a pair of dice.
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968. A coin is biased so that the head is 3 times as likely to occur as tail. If the coin is tossed twice, find the probability distribution of number of tails.
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969. Three cards are drawn successively with replacement from a well-shuffled deck of 52 cards. A random variable X denotes the number of spades in three cards. Determine the probability distribution of X.


Here X takes the values 0, 1, 2, 3.
Let p denote the probability of getting spade.
Now,    straight p space equals 13 over 52 space equals 1 fourth comma space space space space straight q space equals space 1 minus space 1 fourth space equals space 3 over 4
P(X = 0) = straight q space cross times space straight q space cross times space straight q space equals space 3 over 4 cross times 3 over 4 cross times 3 over 4 space equals space 27 over 64

P(X = 1) = straight p space cross times space straight q space cross times space straight q space plus space straight q space cross times space straight p space cross times straight q space plus space straight q space cross times straight q space cross times straight p

               equals space 1 fourth cross times 3 over 4 cross times 3 over 4 plus 3 over 4 cross times 1 fourth cross times 3 over 4 plus 3 over 4 cross times 3 over 4 cross times 1 fourth space equals space 9 over 64 plus 9 over 64 plus 9 over 64 equals 27 over 64

P(X = 2) = straight p space cross times space straight p space cross times space straight q space space plus space straight p space cross times space straight q space cross times space straight p space plus space straight q space cross times space straight p space cross times space straight p

               equals space 1 fourth cross times 1 fourth cross times 3 over 4 plus 1 fourth cross times 3 over 4 cross times 1 fourth plus 3 over 4 cross times 1 fourth cross times 1 fourth space equals space 9 over 64

P(X = 3) = straight p space cross times space straight p space cross times space straight p space equals 1 fourth cross times 1 fourth cross times 1 fourth space equals space 1 over 64
∴ probability distribution is
     
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 Multiple Choice QuestionsShort Answer Type

970. Find the probability distribution of the number of successes in two tosses of a die, where a success is defined as:
number greater than 4
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