The mean of the numbers obtained on throwing a die having writte

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981. In a meeting, 70% of the members favour and 30% oppose a certain proposal. A member is selected at random and we take X = 0 if he opposed, and X = 1 if he is in favour. Find E(X) and Var(X).
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 Multiple Choice QuestionsLong Answer Type

982. Find the variance of the number obtained on a throw of an unbiased die.
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983. A die is tossed twice. Getting a number greater than 4 is considered a success. Find the variance of the probability distribution of the number of successes.
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984. Two bad eggs are mixed accidentally with 10 good ones. Three eggs are drawn at random without replacement from this lot. Find the mean and variance for the number of bad eggs.
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985. Three bad eggs got mixed up with 7 good eggs. If three eggs are drawn (without replacement) from 10 eggs, find the mean and variance for the number of bad eggs among them.
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986. Five defective bulbs are accidentally mixed with twenty good ones. It is not possible to just look at a bulb and tell whether or not a bulb is defective. Four bulbs are drawn at random from this lot. Find the mean number of defective bulbs drawn.
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987. Two cards are drawn simultaneously (or successively, without replacement) from a well-shuffled deck of 52 cards. Compute σ2 for the number of aces.
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988. In a game, a man wins a rupee for a six and loses a rupee for any other number when a fair die is thrown. The man decided to throw a die thrice but to quit as and when he gets a six. Find the expected value of the amount he wins/loses.
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 Multiple Choice QuestionsMultiple Choice Questions

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989. The mean of the numbers obtained on throwing a die having written 1 on three faces, 2 on two faces and 5 on one face is
  • 1

  • 2

  • 5

  • 5


B.

2

Let X denote the number on the die, then X takes values 1, 2 and 5 only.
P(X = 1) = 3 over 6 space equals space 1 half comma space space space space straight P left parenthesis straight X space equals space 2 right parenthesis space equals 2 over 6 space equals 1 third comma space space straight P left parenthesis straight X space equals space 5 right parenthesis space equals space 1 over 6
∴     probability distribution of X is
           
Mean space straight X space equals space sum from blank to blank of straight X space straight P left parenthesis straight X right parenthesis space equals space 1 space cross times 1 half plus 2 cross times 1 third plus 5 space cross times 1 over 6 space equals space 1 half plus 2 over 3 plus 5 over 6 space equals fraction numerator 3 plus 4 plus 5 over denominator 6 end fraction space equals 12 over 6 space equals 2
∴ (B) is correct answer.
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990. Suppose that two cards are drawn at random from a deck of cards. Let X be the number of aces obtained. Then the value of E(X) is
  • 37 over 221
  • 5 over 13
  • 1 over 13
  • 1 over 13
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