1052.A pair of dice is thrown 6 times. If getting a total of 8 is considered a success, what is the probability of (i) at least 4 successes? (ii) at most 5 succcesses?
Here n = 6 p = P{(2, 6), (3, 5), (4, 4), (5, 3), (6, 2) = q = 1 - p = 1 - (i) P(at least 4 successes) = P(4) + P(5) + P(6)
(ii) P(at atmost 5 successess) = 1 - P(6) = 1 - =
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Short Answer Type
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