A pair of dice is thrown 7 times. If getting a total of 7 is considered a success, what is the probability of
(i) no success? (ii) 6 successes? (iii) at least 6 successes? (iv) at most 6 successes?
Here n = 7
Let p be the probability of getting a total of 7.
(i) P(no success) = P(0) =
(ii) P(6 successes) = P(6) =
(iii) P(at least 6 (successes) = P(6) + P(7)
(iv) P(at most 6 successes) = P(not 7 success)