1271.

The number of ways of arranging 8 men and 4 women around a circular table such that no two women can sit together is

• 8!

• 4!

• 8!4!

• $7!{}_8\mathrm{P}_4$

The number of ways of arranging 8 men = 7!

The number of ways of arranging 4 women such that no two women can sit together = ⁸P₄

:. Required number of ways = 7!⁸P₄