If A, B and C are mutually exclusive and exhaustive events of a r

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 Multiple Choice QuestionsMultiple Choice Questions

711.

A student has to answer 10 out of 13 questions in an examination choosing atleast 5 questions from the first 6 questions. The number of choice available to the student is

  • 63

  • 91

  • 161

  • 196


712.

In an entrance test there are multiple choice questions. There are four possible answers to each question, of which one is correct. The probability that a student know the answer to a question is 9/10. If he gets the correct answer to a question, then the probability that he was guessing is 

  • 3740

  • 137

  • 3637

  • 19


713.

There are four machines and it is known that exactly two of them are faulty. They are teste done by one, in a random order till both the faulty machines are identified. Then, the probability that only two tests are need is

  • 13

  • 16

  • 12

  • 14


714.

A random variable X has the probability distribution given below.
X 1 2 3 4 5
P(X = x) K 2K 3K 2K K

Its variance is

  • 163

  • 43

  • 53

  • 103


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715.

A candidate takes three tests in succession and the probability of passing the first test is p. The probability of passing each succeeding test is p or p2 according as he passes or fails in the preceding one. The candidate is selected, if he passes atleast two tests. The probability that the candidate is selected, is

  • p2(2 - p)

  • p(2 - p)

  • p + p2 + p3

  • p2(1 - p)


716.

A six-faced unbiased die is thrown twice and the sum of the numbers appearing on the upper face is observed to be 7. The probability that the number 3 has appeared atleast once, is

  • 15

  • 12

  • 13

  • 14


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717.

If A, B and C are mutually exclusive and exhaustive events of a random experiment such that P(B) = 32P(A) and P(C) = 12P(B), then P(A ∪ C) equals to

  • 1013

  • 313

  • 613

  • 713


D.

713

Given, PB = 32PAand PC = 12PBSince, A, B and C are exclusive events PA + PB + PC = 1 PA + 32PA + 12 × 32PA = 1 PA1 + 32 + 34 = 1 134PA = 1 PA = 413 PC = 12 × 32PA = 34 × 413 = 313Also, A, B and C are mutually exclusive P(A  B) = P(B  C) = P(C  A)=0  P(A  C)= P(A) + P(B) - 0= 413 + 313 = 713


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718.

Two persons A and B are throwing an unbiased six faced dice alternatively, with the condition that the person who throws 3 first wins the game. If A starts the game, then probabilities of A and B to win the same are, respectively

  • 611, 511

  • 511, 611

  • 811, 311

  • 311, 811


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719.

The letters of the word 'QUESTION' are arranged in a row at random. The probability that there are exactly two letters between Q and S is

  • 114

  • 57

  • 17

  • 528


720.

If 1 + 3P3, 1 - 2P2 are probabilities of two mutually exclusive events, then P lies in the interval

  • - 13, 12

  • - 12, 12

  • - 13, 23

  • - 13, 23


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