Represent the following problem situations in the form of quadra

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 Multiple Choice QuestionsLong Answer Type

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9. Represent the following problem situations in the form of quadratic equations:
The area of a rectangular plot is 528 m2. The length of the plot (in metres) is one more than twice its breadth. We need to find the length and breadth of the plot.


Let breadth of the rectangle = x m Then, length of the rectangle = (2x + 1) m
∵   Area of the rectangle = (2x + 1) x m2
According to the given condition,
(2x + 1)x = 528 ⇒ 2x2 + x – 528 = 0
which is a quadratic equation in x.
Solving this equation by factorisation method, we get
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rightwards double arrow   straight x left parenthesis 2 straight x plus 33 right parenthesis minus 16 left parenthesis 2 straight x plus 33 right parenthesis equals 0
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rightwards double arrow                2 straight x plus 33 equals 0 space space or space space straight x space minus space 16 space equals space 0
rightwards double arrow                 space space straight x equals fraction numerator negative 33 over denominator 2 end fraction space space or space space straight x space equals space 16
But breadth cannot be -ve.
∴                                x = 16
Hence, breadth of the rectangle = 16 m and length of the rectangle = 2 x 16 + 1 = 33 m. 

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 Multiple Choice QuestionsShort Answer Type

10. Represent the following problem situations in the form of quadratic equations:
The product of two consecutive positive integers is 306. We need to find the integers.
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