Find the discriminant(or the nature of the roots) of the followi

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40. Find the discriminant(or the nature of the roots) of the following quadratic equations. If the real roots exist, find them
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2x2 – 6x + 3 = 0
Here, a = 2, b = –6, c = 3
Now, D = b2 – 4ac
= (–6)2 – 4(2) (3)
= 36 – 24 = 12
Since, D > 0
Therefore, the given quadratic equation has real and distinct roots.
Now,    straight x space equals space fraction numerator negative straight b plus-or-minus square root of straight D over denominator 2 straight a end fraction equals fraction numerator left parenthesis negative 6 right parenthesis plus-or-minus square root of 2 over denominator 2 cross times 2 end fraction
space space space equals space fraction numerator 6 plus-or-minus 2 square root of 3 over denominator 4 end fraction space equals space fraction numerator 3 plus-or-minus square root of 3 over denominator 2 end fraction
Hence, roots are fraction numerator 3 plus square root of 3 over denominator 2 end fraction comma space fraction numerator 3 minus square root of 3 over denominator 2 end fraction
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