Is it possible to design a rectangular park of perimeter 80 m an

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45.

Is it possible to design a rectangular park of perimeter 80 m and area 400 m2? If so, find its length and breadth.


Let length of the rectangular park be x m and breadth be y m.
According to question,
perimeter = 80 m ⇒ 2(l + b) = 80 m
⇒ 2 (x + y) = 80
⇒ x + y = 40
⇒ y = 40 – x
i.e., breadth = (40 – x)m
Now, area = 400
⇒ l x b = 400
⇒ x(40 – x) = 400
40x – x2 = 400
⇒ x2 – 40x + 400 = 0
Here, a = 1, b = –40, c = 400
Now, D = b– 4ac
= (–40)2 – 4(1) (400) = 1600 – 1600 = 0
Since D = 0
So, the given quadratic equation has equal roots and hence it is possible to design a rectangular park.
Now solving the quadratic equation x2 – 40x + 400 = 0 by quadratic formula, we get
Now,       straight x equals fraction numerator negative straight b plus-or-minus square root of straight D over denominator 2 straight a end fraction
space space space equals fraction numerator negative left parenthesis negative 40 right parenthesis plus-or-minus square root of 0 over denominator 2 cross times 1 end fraction equals 40 over 2 equals 20
Hence, length of the rectangular park (x) = 20 m and breadth = (40 – x) m = 40 – 20 = 20 m.

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