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Quadrilaterals

Long Answer Type

41. In a parallelogram ABCD, E and Fare the mid-points of sides AB and CD respectively. (see figure). Show that the line segments AF and EC trisect the diagonal BD.

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42. Show that the line segments joining the mid-points of the opposite sides of a quadrilateral bisect each other.

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43.

ABC is a triangle right angled at C. A line through the mid-point M of hypotenuse AB and parallel to BC intersects AC at D. Show that:

(i) D is the mid-point of AC (ii) MD ⊥ AC (iii) $CM space equals space MA space equals space 1 half AB.$

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Short Answer Type

44. In triangle ABC, points M and N on sides AB and AC respectively are taken so that

AM equals 1 fourth AB space and space AN equals 1 fourth AC comma space

Prove that MN =

1 fourth

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45. In triangle ABC, points M and N on sides AB and AC respectively are taken so that

AM equals 1 fourth AB space and space AN equals 1 fourth AC comma space Prove space that space MN equals 1 fourth

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46. ABCD is a rhombus and AB is produced to E and F such that AE = AB = BF. Prove that ED and FC are perpendicular to each other.

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Long Answer Type

47. In ∆ABC, AD is the median through A and E is the mid-point of AD. BE is produced to meet AC in F. Prove that

AF equals 1 third AC

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48.

D, E, F are respectively the midpoints of the sides BC, CA and AB of a triangle ABC. Show that:
(i) BDEF is a parallelogram
(ii) DFEC is a parallelogram.

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Short Answer Type

49. In the figure ABCD is a parallelogram and E is the mid-point of side BC. DE and AB on producing meet at F. Prove that AF = 2AB.

Given: ABCD is a parallelogram and E is the mid-point of side BC. DE and AB on producing meet at F.
To Prove: AF = 2AB
Proof: In ∆FAD,
∵ E is the mid-point of BC | Given
and EB || DA
| Opposite sides of a parallelogram are parallel
∴ B is the mid-point of AF | by converse of
mid-point theorem

$therefore space space AB equals BF equals 1 half AF rightwards double arrow space space AF equals 2 AB$

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Long Answer Type

50. ABCD is a trapezium in which side AB is parallel to the side DC and E is the mid-point of side AD (see figure). If F is a point on the side BC such that the segment EF is parallel to the side DC, prove that F is the mid-point of BC and EF =

1 half

(AB + DC).

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