Prove that is irrational.
Squaring on both sides, we get
5b2 = a2
Therefore, 5 divides a2
Therefore, 5 divides a
So, we can write
a = 5c for some integer c.
Substituting for a, we get
5b2 = 25c2
⇒ b2 = 5c2
This means that 5 divides b2, and so 5 divides b.
Therefore, a and b have at least 5 ts a common factor.
But this contradicts the fact that a and b have no common factors other than 1.
This contradiction has arisen because of our incorrect assumption that is rational.
So, we conclude that is irrational.
Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion:
(i)
Without actually performing the long division, state whether the following rational numbers will have a terminating decimal expansion or a non-terminating repeating decimal expansion: