A = {1, 2, 3, 4}
Now, A x A = {1, 2, 3, 4} x {1, 2, 3, 4}
= {(1, 1)(1, 2),(1,3)(1, 4)(2, 1) (2, 2)(2, 3)(2, 4)(3, 1), (3, 2), (3, 3), (3, 4), (4, 1), (4, 2),
(4, 3), (4, 4)}
(i) S = a divides b)
= {(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 4), (3, 3), (4, 4)}
(ii) x is prime}
B = {2, 3}
(iii) S x B = {(1, 1), (1, 2), (1, 3), (1, 4), (2, 2), (2, 4), (3, 3), (4, 4) X (2, 3)
= {(1, 1, 2), (1, 1, 3), (1, 2, 2), (1, 2, 3), (2, 4, 2), (2, 4, 3), (3, 3, 2), (3, 3, 3),
(4, 4, 2), (4, 4, 3)}
The Cartesian product A × A has 9 elements among which are found (–1, 0) and (0,1). Find the set A and the remaining elements of A × A.
Let A = {1, 2}, B = {1, 2, 3, 4}, C={5, 6} and D = {5, 6, 7, 8}. Verify that A x C is a proper subset of B x D.