Let f and g be two functions defined by f(x) =
find (i) f +g (ii) g + f (iii) f - g (iv) g - f (v) gg (vi) gf
The relation f is defined by
and relation g is defined by
Explain, why f is a function and g is not.
If the function g(x) = is differntiable, then the value of k+m is
2
16/5
10/3
10/3
A.
2
Since, g(x) is differentiable ⇒ g(x) must be continuous.
therefore,
At x =3, RHL = 3m+2
and at x = 3, LHL= 2k
therefore, 2k = 3m + 2 ... (i)
Also, g'(x) =
therefore, L{g'(3)} = k/4 and R{g'(3)} = m
⇒ k/4 = m i.e, k = 4m ..... (ii)
On solving eqs (i) and (ii), we get
k = 8/5, m =2/5
⇒ k+m =2
If a ε R and the equation - 3(x-[x]2 + 2(x-[x] +a2 = 0(where,[x] denotes the greatest integer ≤ x) has no integral solution, then all possible value of lie in the interval
(-1,0) ∪ (0,1)
(1,2)
(-2,-1)
(-∞,-2) ∪ (2, ∞)