- 1
- 14
- 13
x ∈ R : 14xx + 1 - 9x - 30x - 4 < 0 = ?
(- 1, 4)
1, 4 ∪ 5, 7
(1, 7)
- 1, 1 ∪ 4, 6
If a, b and n are natural numbers, then a2n - 1 + b2n - 1 is divisible by
a + b
a - b
a3 + b3
a2 + b2
x2 + x + 1x - 1x - 2x - 3 = Ax - 1 + Bx - 2 + Cx - 3⇒ A + C =
4
5
6
8
Let f : R → R be defined byf(x) = α + sinxx, if x> 02, if x = 0β + sinx - xx3, if x < 0where, [x] denotes the integral part of x.If f continuous at x = 0, then β - α is equal to
1
0
2
B.
Given, f(x) = α + sinxx, if x> 02, if x = 0β + sinx - xx3, if x < 0Since, f is continuous at x = 0∴ LHL = f0 = RHL . . .iNow, LHL = limx→0 - f(x) = limx→0 -β + sinx - xx3 =limx→0 β + sinh + h- h3RHL =limx→0 +α + sinxx =limh→0 α + sinhh = α + 1 and f(0) = 2∴ From eq. i, we getβ + 0 = 2 = α + 1 ⇒ β - α = 1
If a, b, c and d ∈ R such that a2 + b2 = 4 and c2 + d2 = 4and if (a + ib) = (c + id)2 (x + iy), then x2 + y2 is equal to
3
If fx = p - xn1n, p > 0 and n is a positive integer, then ffx = ?
x
xn
p1/n
p - xn
If R is the set of all real numbers and f : R - {2} → R is defined by fx = 2 + x2 - x for x ∈ R - 2
R - {- 2}
R
R - {1}
R - {- 1}
Let Q be the set of all rational numbers in [0, 1]and f: [0, 1] → [0,1] be defined by
f(x) = x, for x ∈ Q1 - x for x∉ QThen, the set S = x ∈ 0, 21 : fofx = ?
[0, 1]
- Q
[0, 1] - Q
(0, 1)
If f : R → R, g : R → R are defined by fx = 5x - 3, gx = x2 + 3, then gof - 13 = ?
253
11125
925
25111