Let Q be the set of all rational numbers in [0, 1]and f: [0, 1]&n

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 Multiple Choice QuestionsMultiple Choice Questions

171.

For x  R, the least value of x2 - 6x + 5x2 + 2x + 1 is

  • - 1

  • - 12

  • - 14

  • - 13


172.

x  R : 14xx + 1 - 9x - 30x - 4 < 0 = ?

  • (- 1, 4)

  • 1, 4  5, 7

  • (1, 7)

  • - 1, 1  4, 6


173.

If a, b and n are natural numbers, then a2n - 1  + b2n - 1 is divisible by

  • a + b

  • a - b

  • a3 + b3

  • a2 + b2


174.

x2 + x + 1x - 1x - 2x - 3 = Ax - 1 + Bx - 2 + Cx - 3 A + C = 

  • 4

  • 5

  • 6

  • 8


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175.

Let f :R  R be defined byf(x) = α + sinxx,             if x> 02,                              if x = 0β + sinx - xx3, if x < 0where, [x] denotes the integral part of x.If f continuous at x = 0, then β - α  is equal to

  • - 1

  • 1

  • 0

  • 2


176.

If a, b, c and d ∈ R such that a2 + b2 = 4 and c2 + d2 = 4and if (a + ib) = (c + id)2 (x + iy), then x+ yis equal to

  • 4

  • 3

  • 2

  • 1


177.

If fx = p - xn1n, p > 0 and n is a positive integer, then ffx = ?

  • x

  • xn

  • p1/n

  • p - xn


178.

If R is the set of all real numbers and f : R - {2}  R is defined by fx = 2 +x2 - x for x  R - 2 

  • R - {- 2}

  • R

  • R - {1}

  • R - {- 1}


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179.

Let Q be the set of all rational numbers in [0, 1]and f: [0, 1]  [0,1] be defined by

f(x) = x, for x  Q1 - x for x QThen, the set S = x  0, 21 : fofx = ?

  • [0, 1]

  • - Q

  • [0, 1] - Q

  • (0, 1)


A.

[0, 1]

Given, fx = x for xQ1 - x for x  Q is defined forf0, 1  0, 1If x is rational, thenfx = x ffx = fx = xIf x is irrational, thenfx = 1 - x fofx = f1 - x = 1 - 1 - x= x fofx = x is possible for all values of domain 0, 1


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180.

If f : R  R, g : R  R are defined by fx = 5x - 3, gx = x2 + 3, then gof - 13 = ?

  • 253

  • 11125

  • 925

  • 25111


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