Let f : N → Y be a function defined as f (x) = 4x + 3, where Y

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 Multiple Choice QuestionsMultiple Choice Questions

421.

let f : (-1, 1) → R be a differentiable function
with f(0) = -1 and f'(0) = 1.
Let g(x) = [f(2f(x) + 2)]2. Then g'(0) =

  • 4

  • -4

  • 0

  • 0

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422.

Let f : R → R be a positive increasing function with limit as infinity space rightwards arrow 0 of space fraction numerator straight f left parenthesis 3 straight x right parenthesis over denominator straight f left parenthesis straight x right parenthesis end fraction space equals 1 space then space limit as infinity space rightwards arrow 0 of space fraction numerator begin display style straight f left parenthesis 2 straight x right parenthesis end style over denominator begin display style straight f left parenthesis straight x right parenthesis end style end fraction space space is space equal space to

  • 1

  • 2/3

  • 3/2

  • 3/2

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423.

If for  x ∈ (0, 1/4)  the derivatives tan to the power of negative 1 end exponent space open parentheses fraction numerator 6 straight x square root of straight x over denominator 1 minus 9 straight x cubed end fraction close parentheses space is space square root of straight x. end root space straight g left parenthesis straight x right parenthesis comma then g(x) is equals to 

  • fraction numerator 3 over denominator 1 plus 9 straight x cubed end fraction
  • fraction numerator 9 over denominator 1 plus 9 straight x cubed end fraction
  • fraction numerator 3 straight x square root of straight x over denominator 1 minus 9 straight x cubed end fraction
  • fraction numerator 3 straight x square root of straight x over denominator 1 minus 9 straight x cubed end fraction
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424. integral subscript 0 superscript straight pi[cot x]dx, where [.] denotes the greatest integer function, is equal to
  • π/2

  • 1

  • -1

  • -1

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425.

For real x, let f(x) = x3+ 5x + 1, then

  • f is one–one but not onto R

  • f is onto R but not one–one

  • f is one–one and onto R

  • f is one–one and onto R

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426.

Let f(x) = (x + 1)2– 1, x ≥ – 1
Statement – 1: The set {x : f(x) = f–1(x)} = {0, –1}.
Statement – 2: f is a bijection.

  • Statement–1 is true, Statement–2 is true,Statement–2 is a correct explanation for statement–1 

  • Statement–1 is true, Statement–2 is true; Statement–2 is not a correct explanation for statement–1.

  • Statement–1 is true, statement–2 is false.

  • Statement–1 is true, statement–2 is false.

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427.

Let f(x) = x|x| and g(x) = sinx

Statement 1 : gof is differentiable at x = 0 and its derivative is continuous atthat point
Statement 2: gof is twice differentiable at x = 0

  • Statement–1 is true, Statement–2 is true, Statement–2 is a correct explanation for statement–1

  • Statement–1 is true, Statement–2 is true;Statement–2 is not a correct explanation for statement–1.

  • Statement–1 is true, statement–2 is false.

  • Statement–1 is true, statement–2 is false.

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428.

Let f : N → Y be a function defined as f (x) = 4x + 3, where Y = {y ∈ N : y = 4x + 3 for some x ∈ N}.Show that f is invertible and its inverse is 

  • straight g space left parenthesis straight y right parenthesis space equals space fraction numerator 3 straight y space plus space 4 over denominator 3 end fraction
  • straight g space left parenthesis straight y right parenthesis space equals space 4 plus fraction numerator straight y space plus space 3 over denominator 4 end fraction
  • straight g space left parenthesis straight y right parenthesis space equals fraction numerator straight y space plus space 3 over denominator 4 end fraction
  • straight g space left parenthesis straight y right parenthesis space equals fraction numerator straight y space plus space 3 over denominator 4 end fraction


D.

straight g space left parenthesis straight y right parenthesis space equals fraction numerator straight y space plus space 3 over denominator 4 end fraction

Function is increasing 

straight g space left parenthesis straight y right parenthesis space equals fraction numerator straight y space minus space 3 over denominator 4 end fraction space equals straight x

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429.

Let R be the real line. Consider the following subsets of the plane R × R.
S = {(x, y) : y = x + 1 and 0 < x < 2}, T = {(x, y) : x − y is an integer}. Which one of the following is true?

  • neither S nor T is an equivalence relation on R

  • both S and T are equivalence relations on R

  • S is an equivalence relation on R but T is not 

  • S is an equivalence relation on R but T is not 

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430.

Let f(x) = open curly brackets table attributes columnalign left end attributes row cell left parenthesis straight x minus 1 right parenthesis space sin space open parentheses fraction numerator 1 over denominator straight x minus 1 end fraction close parentheses end cell row cell 0 comma space space space space space space space space space space space space space space space space space space space space space space space space space space space if space straight x space equals 1 space space space space space space space space space space end cell end table close comma space if space straight x space not equal to space 1Then which one of the following is true?

  • f is neither differentiable at x = 0 nor at x = 1

  • f is differentiable at x = 0 and at x = 1

  • f is differentiable at x = 0 but not at x = 1 

  • f is differentiable at x = 0 but not at x = 1 

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