Short Answer TypeIf the GP.’s 5,10, 20, .......and 1280, 640, 320, ......have their nth terms equal, find the value of n.
Find all the sequences which are simultaneously in A.P. and GP.
Let the sequence 
be in A.P. as well as in G.P.
Let 
be three consecutive terms of an A.P.
∴ 
or 
...(i)
Let r be the common ratio of G.P.
∴ 
and 
and 
in (i), we get
![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>](/application/zrc/images/qvar/MAEN11032709-13.png)
r = 1∴ 
Hence, all the constant sequences are the only sequences which are in A.P. as well as in G.P.
In a finite GP. the product of the terms equidistant from the beginning and the end is always same and equal to the product of first and last term.
If the first and the nth terms of a GP. are a and b respectively and if P is the product of first n terms, prove that P2 = (ab)n.
Long Answer TypeShort Answer TypeIf 4th, 10th and 16th terms of a GP. are x, y and z respectively, Prove that y, z are in GP.
Switch
show that a, b, c, d are in G.P.
