Sum the series from Mathematics Sequences and Series

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 Multiple Choice QuestionsShort Answer Type

71.

Show that products of the corresponding terms of sequences a, ar, ar2, .........ar n – 1 and A, AR, AR2, ........ An – 1 form a GP. and find common ratio.

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72.

The first term of GP. is 1. The sum of 3rd and 5th term is 90. Find the common ratio of G.P.

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73.

Find the sum of the indicated terms of each of the following CP’s:

3, 6, 12, ........; 7 terms

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74.

Find the sum of the indicated terms of each of the following CP’s:

square root of 7 comma space square root of 21 comma space 3 square root of 7 comma space........ semicolon space space straight n space terms

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75.

Find the sum to indicated number of terms in each of the geometric progressions:

1, - a, straight a squared comma spacenegative straight a cubed comma space space space..... semicolon space n terms left parenthesis straight a not equal to space minus 1 right parenthesis

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76.

Find the sum to indicated number of terms in each of the geometric progressions:

open parentheses 1 fifth plus 2 over 5 squared plus 3 over 5 cubed close parentheses comma space space open parentheses 1 over 5 to the power of 4 plus 2 over 5 to the power of 5 plus 3 over 5 to the power of 6 close parentheses comma space open parentheses 1 over 5 to the power of 7 plus 2 over 5 to the power of 8 plus 3 over 5 to the power of 9 close parentheses comma space...... semicolon 7



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77.

Find the sum of n terms of sequence

open parentheses straight x plus 1 over straight x close parentheses squared comma space space open parentheses straight x squared plus 1 over straight x squared close parentheses squared comma space space open parentheses straight x cubed plus 1 over straight x cubed close parentheses squared comma space space............

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78.

Prove that the sum to n terms of the series

11 + 103 + 1005 +........  is <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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#6 {main}</pre>

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79.

Find the sum to n terms of the sequence space space open curly brackets straight t subscript straight n close curly brackets given by <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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80.

Sum the series

space space 2 over 9 space plus space 1 third plus space 1 half plus space............ space plus space 81 over 32


The given series is : <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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Here,  space space straight a equals 2 over 9 comma space space straight r space equals space fraction numerator begin display style 1 third end style over denominator begin display style 2 over 9 end style end fraction space equals space 1 third.9 over 2 equals 3 over 2.

Let    l space equals space 81 over 32 be the nth term

Required sum  = fraction numerator straight a minus lr over denominator 1 minus straight r end fraction space equals space fraction numerator begin display style 2 over 9 end style minus begin display style 81 over 32 end style open parentheses begin display style 3 over 2 end style close parentheses over denominator 1 minus begin display style 3 over 2 end style end fraction space equals space fraction numerator begin display style 2 over 9 end style minus begin display style 243 over 64 end style over denominator begin display style fraction numerator negative 1 over denominator 2 end fraction end style end fraction space equals space fraction numerator 128 minus 2187 over denominator 9.64 end fraction open parentheses fraction numerator negative 2 over denominator 1 end fraction close parentheses space equals space fraction numerator 2059 over denominator 9. space 32 space end fraction space equals space 2059 over 288



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