Sum the following series:0.5 + 0.55 + 0.555.......... to n terms

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 Multiple Choice QuestionsShort Answer Type

81.

How many terms of the sequence

space space square root of 3 comma space 3 comma space 3 square root of 3 comma space........ must be taken to make the sum <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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82.

Sum the following series:

7 + 77 + 777 + ......... to n terms

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83.

Sum the following series:

0.5 + 0.55 + 0.555.......... to n terms




Let space space straight S subscript straight n = 0.5 + 0.55 + 0.555 +............ to n terms

           = 5[0.1 + 0.11 + 0.111 + ........... to n terms]

           = 5 over 9 left square bracket 0.9 space plus space 0.99 space plus space 0.999 space plus space.......... space to space straight n space terms right square bracket

           = 5 over 9 left square bracket left parenthesis 1 minus 0.1 right parenthesis space plus space left parenthesis 1 minus.01 right parenthesis space plus space left parenthesis 1 minus.001 right parenthesis space plus space....... space to space straight n space terms right square bracket

           = 5 over 9 open square brackets straight n minus open parentheses 1 over 10 plus 1 over 100 plus 1 over 1000 plus....... space to space straight n space terms close parentheses close square brackets

           = 5 over 9 open square brackets straight n minus fraction numerator begin display style 1 over 10 end style open parentheses 1 minus begin display style 1 over 10 to the power of straight n end style close parentheses over denominator 1 minus begin display style 1 over 10 end style end fraction close square brackets space equals space 5 over 9 open square brackets straight n minus 1 over 9 open parentheses 1 minus 1 over 10 to the power of straight n close parentheses close square brackets space equals space 5 over 81 open square brackets 9 straight n minus 1 space plus space 1 over 10 to the power of straight n close square brackets
          

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84.

Given a G.P. with a = 729 and 7th term 64, determine S7.

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85.

Determine the number of terms in a GP., if t1 = 3, tn = 96 and Sn = 189.

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86.

Find the least value of n for which the sum 1 + 3 + 32+ ...... to n terms is greater than 7000.

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87.

The ratio of the sum of first three terms is to that of first 6 terms of a G.P. is 125 : 152. Find the common ratio.

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88.

If S1, S2 and S3 be respectively the sums of n, 2n and 3n terms of a GP., prove that S1 (S3 – S2) = (S2 – S1)2

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 Multiple Choice QuestionsLong Answer Type

89.

Let S be the sum, P the product and R the sum of the reciprocals of n terms in a G.P. Prove that straight P squared straight R to the power of straight n space equals space straight S to the power of straight n.

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 Multiple Choice QuestionsShort Answer Type

90.

Evaluate:

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