The A.M. of two numbers is 3 times their G.M. Show that the numb

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 Multiple Choice QuestionsShort Answer Type

91.

Evaluate:

space space sum from straight i equals 1 to 10 of open square brackets open parentheses 1 half close parentheses to the power of straight i minus 1 end exponent plus open parentheses 1 fifth close parentheses to the power of straight i plus 1 end exponent close square brackets

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92.

Find the sum of the products of the corresponding terms of sequences 2, 4, 8, 16, 32 and 128, 32, 8, 2, 1 half.


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93.

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#6 {main}</pre>, find the value of n.

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94.

If A and G are respectively the A.M. and G.M. between the two distinct positive numbers are a and b, then Prove A>G.

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95.

If A and G are respectively the A.M. and G.M. between two positive numbers a and b, then proof the quardratic equation having a, b as it roots is straight x squared minus 2 Ax plus straight G squared equals 0.

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96.

If A and G be A.M. and G.M. between two positive numbers, then the numbers are

straight A plus-or-minus square root of straight A squared minus straight G squared end root.

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97.

The A.M. between two positive numbers is 34 and their GM. is 16. Find the numbers.

155 Views

98.

Find two positive numbers whose difference is 12 and whose A.M. exceeds the GM. by 2.

900 Views

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99.

Find the value of n so that fraction numerator straight a to the power of straight n plus 1 end exponent plus straight b to the power of straight n plus 1 end exponent over denominator straight a to the power of straight n plus straight b to the power of straight n end fraction may be the G.M. between a and b.

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100.

The A.M. of two numbers is 3 times their G.M. Show that the numbers are in the ratio

3 plus 2 square root of 2 colon space space 3 minus 2 square root of 2.


Let a and b be two numbers.

                       A.M = fraction numerator straight a plus straight b over denominator 2 end fraction comma  G.M. = space space square root of ab

According to the given condition fraction numerator straight a plus straight b over denominator 2 end fraction space equals space 3 square root of ab space rightwards double arrow space fraction numerator straight a plus straight b over denominator 2 square root of ab end fraction space equals space 3 over 1

Applying componendo and dividendo, we get

                 fraction numerator straight a plus straight b plus 2 square root of ab over denominator straight a plus straight b minus 2 square root of ab end fraction space equals space fraction numerator 3 plus 1 over denominator 3 minus 1 end fraction space space space rightwards double arrow space space space space space fraction numerator left parenthesis square root of straight a plus square root of straight b right parenthesis squared over denominator left parenthesis square root of straight a minus square root of straight b right parenthesis end root squared end fraction space equals space 4 over 2

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#6 {main}</pre>

Again applying componendo and dividendo, we get

fraction numerator square root of straight a plus square root of straight b plus square root of straight a minus square root of straight b over denominator square root of straight a plus square root of straight b minus square root of straight a plus square root of straight b end fraction space equals space fraction numerator 2 plus square root of 2 over denominator 2 minus square root of 2 end fraction space space space space rightwards double arrow space space space space space fraction numerator 2 square root of straight a over denominator 2 square root of straight b end fraction space equals space fraction numerator 2 plus square root of 2 over denominator 2 minus square root of 2 end fraction


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#6 {main}</pre>

Squaring both sides, we get

               straight a over straight b space equals space fraction numerator 4 plus 2 plus 2 left parenthesis 2 right parenthesis square root of 2 over denominator 4 plus 2 minus 2 left parenthesis 2 right parenthesis square root of 2 end fraction

rightwards double arrow           straight a over straight b space equals space fraction numerator 6 plus 4 square root of 2 over denominator 6 minus 4 square root of 2 end fraction space equals space fraction numerator 3 plus 2 square root of 2 over denominator 3 minus 2 square root of 2 end fraction

∴    Numbers are in ratio 3 plus 2 square root of 2 colon 3 minus 2 square root of 2




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