If a, b, c are in G.P. and x, y are the arithmetic means of a, b and b, c respectively,
then prove that and
If a, b, c are in A.P. and x,y,z are in G.P., show that
Since a, b, c are in A.P.
∴ b - a = c - b 2b = c + a
Here, x, y, z are in G.P.
Let r be the common ratio
∴ y = xr, z = xr2
Now,
[By using (i)]
= 1 . 1 = 1
∴