If x and y are digits such that 17! = 3556xy428096000, then x + y equals
15
6
12
13
A.
15
Given, 17! = 3556xy428096000
Since. 17! is divisible by 9, so sum of the digits (48 + x + y) must be divisible by 9.
So, x + y can be 15 or 6
Also, 17! is divisible by 11, so [10 + x - y] must be multiple of 11 or 0. The only possibility is
Let f(x) = x + 1/2. Then, the number of real values of x for which the three unequal terms f(x), f(2x), f(4x) are in HP is
1
0
3
2
For every real number x,
let f(x) = Then, the equation f(x) = 0 has
no real solution
exactly one real solution
exactly two real solutions
infinite number of real solutions