The greatest positive integer which divides (n + 16)(n + 17)(n +

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 Multiple Choice QuestionsMultiple Choice Questions

341.

If a + bx - 3 = 127 + 13x + ... , then the ordered pair a, b = ?

  • (3, - 27)

  • 1, 13

  • (3, 9)

  • (3, - 9)


342.

The value of the sum 1 · 2 . 3 + 2 . 3 . 4 + 3 . 4 . 5 +  ... upto n terms is equal to

  • 16n22n2 + 1

  • 16n2 - 12n - 12n + 3

  • 18n2 + 1n2 +5

  • 14nn +1n + 2n + 3


343.

If a, b, c are distinct and the roots of (b - c)x2 + (c - a)x + (a - b) = 0 are equal, then a, b and c are in

  • anthmet1c progression

  • geometnc progression

  • harmonic progression

  • arithmetico-geometnc progression


344.

If the roots of x3 - kx2 + 14x - 8 = 0 are in geometric progression, then k is equal to

  • - 3

  • 7

  • 4

  • 0


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345.

The number of four-digit numbers formed by using the digits 0, 2, 4, 5 and which are not divisible by 5, is

  • 10

  • 8

  • 6

  • 4


346.

If x = 15 + 1 . 35 . 10 + 1 . 3 . 55 . 10 . 5 +... ,3x2 + 6x = ?

  • 1

  • 2

  • 3

  • 4


347.

In ABC, a + b + cb + c - a = λbc, then

  • λ < - 6

  • λ > 6

  • 0 < λ <  4

  • λ > 4


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348.

The greatest positive integer which divides (n + 16)(n + 17)(n + 18)(n +19), for all positive integers n, is

  • 6

  • 24

  • 28

  • 20


B.

24

We have, (n + 16)(n + 17)(n + 18)(n + 19)These numbers are the product of four consecutive natural number Thus number divides by 4! = 24


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349.

If x1, x2, x3 as well as y1, y2, yare in geometric progression with the same common ratio,then the points, x1, y1, x2, y2, x3, y3 are

  • vertices of an equilateral triangle

  • vertices of a right angled triangle

  • vertices of a right angled isosceles triangle

  • collinear


350.

If 124 + 2x2 = 2433x2 - 2, then x is equal to

  • ± 1312

  • ± 145

  • ± 1213

  • ± 514


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