Let U ={1,2,3,4,5,6,7,8,9}
A = {1, 2, 3, 4}, B = {2, 4, 6, 8}, C = {3, 4, 5, 6}
Find (a) A' (b) B' (c)(A ∪ C)' (d) (A ∪ B)' (e) (A')' (f) (B-C)'
Fill in the blanks to make each of the following a true statement : (i) A ∪ A′ = . . . (ii) φ′ ∩ A = . . . (iii) A ∩ A′ = . . . (iv) U′ ∩ A = . . .
Id U = {1, 2, 3, 4, 5, 7, 8, 9}, A = {2, 4, 6, 8} , B ={2, 3, 5, 7} verify De Morgan's laws:
Taking the set of natural numbers as the universal set, write down the complements of the following sets :
(i) {x : x is an even natural number} (ii) {x : x is an odd natural number}
(iii) {x : x is a positive multiple of 3} (iv) {x : x is a prime number}
(v) {x : x is a natural number divisible by 3 and 5}
(vi) {x : x is a perfect square} (vii) {x : x is a perfect cube}
(viii) { x : x + 5 = 8 } (ix) { x : 2x + 5 = 9}
(x) { x : x ≥ 7 } (xi) {x : x ∈ N and 2x + 1 > 10}
∴ A ' = U - A =
= {x : x is an odd natural number}
(ii) A = {x : x is an odd number}
A' = U - A = - {x : x is an odd number}
= {x : x is an even natural number} =
(iii) A = {x : x is a positive multiple of 3}
A' = U - A = {1, 2, 3, 4, 5, 6, .......} - {3, 6, 9, 12, .........}
= {1, 2, 4, 5, ...........} = , x is not a multiple of 3}
(iv) A = {x : x is a prime number} = , x is priime number}
A' = U - A = - x is a prime number
= , x is not a prime number}
(v) A = , x is divisible by 3 and 5}
=, x is divisible by 15.
A' = U - A = , x is divisible by 15}
= , x is not divisible by 15}
= , x is not divisible by 3 and 5}
(vi) A = { x : x is a perfect square}
A' = U - A = - (x : x is a perfect square)
= , x is not a perfect square}
(vii) A = {x : x is a perfect cube}
A' = U - A = - {x : x is a perfect cube}
= , x is not a perfect cube}
(viii) A = {x : x +5 = 8} = {x : x = 3} = {3}
∴ A' = U - A = {1, 2, 3, 4, 5, 6, .........} - {3} = {1, 2, 3, 4, 5, 6, .........}
∴ A' =
(ix) A = { x : 2x + 5 = 9} = {x : 2x = 4} = {x : x = 2} = {2}
∴ A' = U - A = {1, 2, 3, 4, 5, 6, ..........} - {3} = {1, 2, 4, 5, 6, ............}
(x) A =
A' = U - A =
= {1, 2, 3, 4, 5, 6}
(xi)
∴ A' = U - A = {1, 2, 3, 4, 5, 6, 7, 8, .........} - {5, 6, 7, 8, ..........}
= {1, 2, 3, 4}