Let C and D be the position of two aeroplanes. The height of the aeroplane which is at point D be 3000 m and it passes another aeroplane vertically which is at point C. Let BC = x m. It is also given that the angles of elevation of two planes from the point A on the ground is 45° and 60° respectively.
In right triangle ABC, we have
In right triangle ABD, we have
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Comparing (i) and (ii), we get
Hence, vertical distance between the aeroplane
= CD = BD - BC