Let A be the position of boy D, be the position of girl and F be the position of kite, such that AF - 100 m; CD = 20 m; ∠BAF = 30° and ∠EDF = 45°
In right triangle ABF, we have
Let DF be the length of the second kite.
Now, in right triangle DEF, we have
Hence, the length of te string =
Hence, the usual speed of the aircraft be x km/hr = 750 km/hr.