A man standing on the deck of a ship, which is 10 m above water

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 Multiple Choice QuestionsShort Answer Type

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171.

A man standing on the deck of a ship, which is 10 m above water level, observes the angle of elevation of the top of a hill as 60° and the angle of depression of the base of a hill as 30°. Find the distance of the hill from the ship and the height of the hill.




Let CD be the hill and suppose the man is standing on the deck of a ship at point A.

The angle of depression of the base C of the hill CD observed from A is 30° and the angle of elevation of the top D of the hill CD observed from A is 60°.
therefore angle EAD space equals space 60 degree space and space angle BCA space equals 30 degree
In space increment AED comma
tan space 60 degree space equals DE over EA
therefore square root of 3 space equals straight h over straight x
therefore space straight h equals square root of 3 straight x space space... space left parenthesis 1 right parenthesis
In space increment ABC comma
tan space 30 degree space equals space AB over BC
therefore space fraction numerator 1 over denominator square root of 3 end fraction equals 10 over straight x
therefore space straight x equals 10 square root of 3 space in space equation space left parenthesis 1 right parenthesis comma space we space get
straight h equals square root of 3 space straight x 10 square root of 3 space equals space 10 straight x 3 space equals 30
therefore space DE space equals space 30 space straight m
therefore space CD equals CE plus ED space equals 10 plus 30 space equals space 40 space straight m
Thus comma space the space distance space of space the space hill space from space the space ship space is space 10 square root of 3 space straight m space and space
the space height space of space the space hill space is space 40 space straight m.
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172.

The angle of elevation of the top Q of a vertical tower PQ from a point X on the ground is 60o. From a point Y, 40 m vertically above X, the angle of elevation of the top Q of the tower is 45o. Find the height of the tower PQ and the distance PX. Use square root of 3 space equals 1.73

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173.

In Given figure, a tower AB is 20 m high and BC, its shadow on the ground, is m20 square root of 3 long. Find the sun's altitude.

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174. The angle of elevation of an aeroplane from a point A on the ground 60°. After a flight of 15 seconds, the angle of elevation changes to 30°. If the aeroplane is flying at a constant height of 1500 space square root of 3 space end root space straight m, find the speed of the plane in km/hr.

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 Multiple Choice QuestionsLong Answer Type

175. At a point A, 20 metres above the level of water in a lake, the angle of elevation of a cloud is 30°. The angle of depression of the reflection of the cloud in the lake, at A is 60°. Find the distance of the cloud from A.
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 Multiple Choice QuestionsShort Answer Type

176.

The ratio of the height of a tower and the length of its shadow on the ground is √3:1. What is the angle of elevation of the sun?

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177.

A moving boat is observed from the top of a 150 m high cliff moving away from the cliff. The angle of depression of the boat changes from 60° to 45° in 2 minutes. Find the speed of the boat in m/h.

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 Multiple Choice QuestionsLong Answer Type

178.

The angle of elevation of a cloud from a point 60 m above the surface of the water of a lake is 30° and the angle of depression of its shadow in water of lake is 60°. Find the height of the cloud from the surface of the water. 

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 Multiple Choice QuestionsShort Answer Type

179.

As observed from the top of a 100 m high light house from the sea-level, the angles of depression of two ships are 30° and 45°. If one ship is exactly behind the other on the same side of the light house, find the distance between the two ships. [ Use √3= 1.732 ]


 Multiple Choice QuestionsMultiple Choice Questions

180.

The angle of depression of a car, standing on the ground, from the top of a 75 m high tower, is 30o. The distance of the car from the base of the tower (in m.) is

  • 25√3

  • 50√3

  • 75√3

  • 150


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