A Pythagorean triplet is given by:
n, n2 – 1 and n2 + 1
2n, n2 – 1 and n2 + 1
2n, 2n2 - 1 and 2n2 + 1
If the number of digits of a perfect square is ‘n’ and n is ‘even’, then what is number of digits of its square root?
If the number of digits of a perfect square is ‘n’ and n is an odd number, then what-is the number of digits of its square root?