Short Answer Type(–1) = 1. Is –1, a square root of 1?
(–2)2 = 4. Is –2, a square root of 4?
(–9)2 = 81. Is –9, a square root of 81?
(i) Since (–1) × (–1) = 1
i.e. (–1)2 = 1
∴ Square root of 1 can also be –1.
Similarly,
(ii) Yes (–2) is a square root of 4.
(iii) Yes (–9) is a square root of 81.
Since we have to consider the positive square roots only and the symbol for a positive square root is 
.
∴ 
= 4 (and not (-4)
Similarly, 
means, the positive square root of 25 i.e. 5.
We can also find the square root by subtracting successive odd numbers starting from 1.
Long Answer TypeBy repeated subtraction of odd numbers starting from 1, find whether the following numbers are perfect squares or not? If the number is a perfect square, then find its square root.
(i) 121 (ii) 55 (iii) 36
(iv) 49 (v) 90
Short Answer TypeWhat could be the possible ‘one’s’ digits of the square root of each of the following numbers?
(i) 9801 (ii) 99856 (iii) 998001 (iv) 657666025
Without doing any calculation, find the numbers which are surely not perfect squares.
(i) 152 (ii) 257 (iii) 408 (iv) 441
Can we say that if a perfect square is of n-digits, then its square root will have 
digits if n is even of 
if n is odd?
Without calculating square roots, find the number of digits in the square root of the following numbers.
(i) 25600 (ii) 100000000 (iii) 36864
Find the number of digits in the square root of each of the following numbers (without any calculation).
(i) 64 (ii) 144 (iii) 4489
(iv) 27225 (v) 390625
Fill In the Blanks
Switch
(ii)
(iii) 
(iv)
