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Surface Areas and Volumes

Short Answer Type

531. A hemispherical tank of radius 1.75 m is full of water it is connected with a pipe which empties it at the rate of 7 litres per second. How much time will it take to empty the tank completely.

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532. Four right circular cylindrical vessels each having diameter 21 cm. and height 38 cm. are full of icecream. The icecream is to be filled in cones of height 12 cm and diameter 7cm having hemispherical shape at the top. Find the total number of such cones which can be filled with icecream.

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Long Answer Type

533. A wooden article was made by scooping out a hemisphere from each end of a solid cylinder. If the height of the cylinder is 20 cm and radius of the base is 3.5 cm, find the total surface area of the article.

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534.

The decorative block shown in fig. is made of two solids - a cube and a hemisphere. The base of the block is a cube with edge 5 cm, and the hemisphere fixed on the top has a diameter of 4.2 cm. Find the total surface area of the block.

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Short Answer Type

535. Mayank made a bird-bath for his garden in the shape of a cylinder with a hemispherical depression at one end. The height of the cylinder is 1.45 m and its radius is 30 cm. Find the total surface area of the birth - bath.

open parentheses bold pi bold space bold equals bold space bold 22 over bold 7 close parentheses bold space bold space

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536. A rocket is in the form of a circular cylinder closed at the lower end and a cone of the same radius is attached to the top The radius of the cylinder is 2.5 m, its height is 21 m and the slant height of the cone is 8 m. Calculate the total surface area of the rocket.

Let r m be the radius, and h m be the height of the cylinder, then
r = 2.5 m and h = 21 m
Let r m be the radius and l m be the slant height of the cone, then
r₁ = 2.5 m and l = 8 m
Now,
The Total Surface Area of the rocket
= C.S.A of cone + C.S.A of cylinder + Area of base
= $straight pi$ r₁l + 2 $straight pi$ rh + $straight pi$ r²= $straight pi$ rl + 2 $straight pi$ rh + $straight pi$ r² [r₁ = r]
= $straight pi$ r (l + 2h + r)

$equals space open square brackets 22 over 7 straight x space 2.5 space left parenthesis 8 space plus 2 space straight x space 21 space plus space 2.5 close square brackets space straight m squared equals space open square brackets 22 over 7 straight x space 2.5 space straight x space 52.5 close square brackets space straight m squared equals space open parentheses fraction numerator 2887.5 over denominator 7 end fraction close parentheses straight m squared space equals space 412.5 space straight m squared$

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Long Answer Type

537. A toy is in the form of a cone mounted on a hemisphere of common base radius 7cm. The total height of the toy is 31 cm. Find the total surface area of the toy.

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538. The interior of building is in the form of a right circular cylinder of radius 7 m and height 6 m, surmounted by a right circular cone of same radius and of vertical angle 60°. Find the cost of painting the building from inside at the rate of Rs. 30/m².

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539. A solid is composed of a cylinder with hemispherical ends. If the whole length of the solid is 100 cm and the diameter of the hemispherical ends is 28 cm, find the cost of polishing the surface of the solid at the rate of 5 paise per sq. cm.

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Short Answer Type

540. A solid toy is in the form of a hemisphere surmounted by a right circular cone. The height of the cone is 2 cm and the diameter of the base is 4 cm. Determine the volume of the toy. If a right circular cylinder circumscribes the toy.
Find the difference of the volumes of the cylinder and the toy.

(Use π = 3.14).

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