Volume and surface area of a solid hemisphere are numerically equal. What is the diameter of the hemisphere?
The 3/4th part of a conical vessel of internal radius 5 cm and height 24 cm is full of water. The water is emptied into a cylindrical vessel with internal radius 10 cm. Find the height of water in a cylindrical vessel.
In the given figure, OACB is a quadrant of a circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the shaded region.
In a hospital used water is collected in a cylindrical tank of diameter 2 m and height 5 m. After recycling, this water is used to irrigate a park of the hospital whose length is 25 m and breadth is 20 m. If the tank is filled completely then what will be the height of standing water used for irrigating the park. Write your views on recycling of water.
In the given figure, the side of square is 28 cm and radius of each circle is half of the length of the side of the square where O and O' are centres of the circles. Find the area of shaded region.
The height of a cone is 10 cm. The cone is divided into two parts using a plane parallel to its base at the middle of its height. Find the ratio of the volumes of the two parts.
Let the height and radius of the given cone be H and R respectively.
The cone is divided into two parts by drawing a plane through the mid point of its axis and parallel to the base.
Upper part is a smaller cone and the bottom part is the frustum of the cone.
⇒ OC = CA = h/2
Let the radius of smaller cone be r cm.
In Δ OCD and Δ OAB,
∠OCD = ∠OAB = 90°
∠COD = ∠AOB (common)
∴ Δ OCD ∼ Δ OAB (AA similarity)
⇒ OA/OC = AB/CD = OB/OD
⇒ h / h/2 = R/r
⇒ R = 2r
The radius and height of the cone OCD are r cm and h/2 cm
Therefore the volume of the cone OCD = 1/3 x π x r2 x h/2 = 1/6 πr2h
Volume of the cone OAD = 1/3 x π x R2 x h = 1/3 x π x 4r2 x h
The volume of the frustum = Volume of the cone OAD - Volume of the cone OCD
= (1/3 x π x 4r2 x h) – (1/3 x π x r2 x h/2)
= 7/6 πr2h
Ratio of the volume of the two parts = Volume of the cone OCD : volume of the frustum
= 1/6 πr2h : 7/6 πr2h
= 1 : 7
If A(–2, 1), B(a, 0), C(4, b) and D(1, 2) are the vertices of a parallelogram ABCD, find the values of a and b. Hence find the lengths of its sides.