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Inner Radius (r) = 6 cm Outer Radius (R) = 6 cm + 1 cm = 7 cm Total surface area of the bowl = 2πr 2 + 2πR 2 + π(R 2 – r 2 ) = 2π(6) 2 + 2π(7) 2 + π(7 2 – 6 2 ) = 72π + 98π+ 13π = 183π cm 2

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101. A hemispherical bowl made of steel is of 1 cm thickness. The inner radius of the bowl is 6 cm. Find the total surface area of the bowl, in terms of π.

Inner Radius (r) = 6 cm
Outer Radius (R) = 6 cm + 1 cm = 7 cm
Total surface area of the bowl
= 2πr² + 2πR² + π(R² – r²)
= 2π(6)² + 2π(7)² + π(7² – 6²)
= 72π + 98π+ 13π
= 183π cm²

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102. Find the surface area of a sphere of radius 7 cm.

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103. Find the surface area of a sphere of radius 7 cm.

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104. The hollow sphere, in which the circus motorcyclist performs his stunts, has a diameter of 7 m. Find the area available to the motorcyclist for riding.

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105.

A hemispherical dome of a Stupa needs to be painted. If the circumference of the base of the dome is 17.6 m, find the cost of painting it, given the cost of painting is र 5 per 100 cm².

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106. A hemispherical dome of a building needs to be painted. If the circumference of the base of the dome is 17.6 cm, find the cost of painting it, if the cost of painting is र 5 per 100 cm².

open parentheses Take space straight pi equals 22 over 7 close parentheses

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107.

The internal and external diameters of a hollow hemispherical vessel are 24 cm and 25 cm respectively. The cost to paint 1 sq. cm of surface is र 1.75. Find the total cost to the nearest rupee to paint the vessel all over. Ignore the area of the edge. (Take $straight pi$ = 3.14)

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108. A hemispherical dome is to be painted from the inside. The circumference of the dome is 176 m. Find the area to be painted.

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109. The diameter of a sphere is decreased by 25%. By what percent will its curved surface area be decreased?

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110.

A hemispherical dome of a building needs to be painted. If the area of the base is 24.64 m², find the cost of painting it, given the cost of painting is र 5 per 100 m².

$open parentheses Use space straight pi space equals 22 over 7 close parentheses$