A plane P meets the coordinate axes at A, B and C respectively. The centroid of $∆$ABC is given to be (1, 1, 2). Then the equation of the line through this centroid and perpendicular to the plane P is:

• $\frac{\mathrm{x} - 1}{2} = \frac{\mathrm{y} - 1}{1} = \frac{\mathrm{z} - 2}{1}$

• $\frac{\mathrm{x} - 1}{1} = \frac{\mathrm{y} - 1}{2} = \frac{\mathrm{z} - 2}{2}$

• $\frac{\mathrm{x} - 1}{1} = \frac{\mathrm{y} - 1}{1} = \frac{\mathrm{z} - 2}{2}$

• $\frac{\mathrm{x} - 1}{2} = \frac{\mathrm{y} - 1}{2} = \frac{\mathrm{z} - 2}{1}$