Find the angle between the following pair of lines:  from Math

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 Multiple Choice QuestionsShort Answer Type

71. Find the angle between the lines whose direction ratios are a, b, c and b – c, c – a, a – b.
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72. Find the angle between each of the following pairs of lines:
fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator negative 2 end fraction comma space space straight z space equals space 2 comma space space space fraction numerator straight x minus 1 over denominator 1 end fraction space equals space fraction numerator 2 straight y plus 3 over denominator 3 end fraction space equals space fraction numerator straight z plus 5 over denominator 2 end fraction

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73. Find the angle between pair of lines:
                   fraction numerator straight x plus 3 over denominator 3 end fraction space equals space fraction numerator straight y minus 1 over denominator 5 end fraction space equals space fraction numerator straight z plus 3 over denominator 4 end fraction

and          fraction numerator straight x plus 1 over denominator 1 end fraction space equals space fraction numerator straight y minus 4 over denominator 1 end fraction space equals space fraction numerator straight z minus 5 over denominator 2 end fraction
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74. Find the angle between the following pair of lines:
fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 1 over denominator 5 end fraction space equals fraction numerator straight z plus 3 over denominator negative 3 end fraction space space and space space fraction numerator straight x plus 1 over denominator negative 1 end fraction space equals space fraction numerator straight y minus 4 over denominator 8 end fraction space equals space fraction numerator straight z minus 5 over denominator 4 end fraction
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75. Find the angle between the following pair of lines:
fraction numerator 5 minus straight x over denominator 3 end fraction space equals space fraction numerator straight y plus 3 over denominator negative 2 end fraction comma space space straight z space equals space 5 space space space and space space straight x over 1 space equals space fraction numerator 1 minus straight y over denominator 3 end fraction space equals fraction numerator straight z minus 5 over denominator 2 end fraction

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76. Find the angle between the following pair of lines:
 straight x over 2 space equals space straight y over 2 space equals space straight z over 1 space space and space space fraction numerator straight x minus 5 over denominator 4 end fraction space equals space fraction numerator straight y minus 2 over denominator 1 end fraction space equals space fraction numerator straight z minus 3 over denominator 8 end fraction


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77. Find the angle between the following pair of lines:
fraction numerator straight x minus 5 over denominator 1 end fraction equals space fraction numerator 2 straight y plus 6 over denominator negative 2 end fraction space equals space fraction numerator straight z minus 3 over denominator 1 end fraction space space and space fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction
 



The equations of two lines are
                    fraction numerator straight x minus 5 over denominator 1 end fraction space equals space fraction numerator 2 straight y plus 6 over denominator negative 2 end fraction space equals space fraction numerator straight z minus 3 over denominator 1 end fraction space and space space fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction

or               fraction numerator straight x minus 5 over denominator 1 end fraction space equals space fraction numerator straight y plus 3 over denominator negative 1 end fraction space equals space fraction numerator straight z minus 3 over denominator 1 end fraction space space and space space fraction numerator straight x minus 2 over denominator 3 end fraction space equals space fraction numerator straight y plus 1 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator 5 end fraction
Direction ratios of two lines are 1, –1, 1 and 3, 4, 5.
Let θ be angle between the lines.
therefore space space space space cos space straight theta space equals space fraction numerator left parenthesis 1 right parenthesis thin space left parenthesis 3 right parenthesis space plus space left parenthesis negative 1 right parenthesis thin space left parenthesis 4 right parenthesis space plus space left parenthesis 1 right parenthesis thin space left parenthesis 5 right parenthesis over denominator square root of 1 plus 1 plus 1 end root space square root of 9 plus 16 plus 25 end root end fraction space equals space fraction numerator 3 minus 4 plus 5 over denominator square root of 3 space square root of 50 end fraction
                    equals space fraction numerator 4 over denominator square root of 3 space cross times space 5 square root of 2 end fraction space equals space fraction numerator 4 over denominator 5 square root of 6 end fraction
therefore space space space space straight theta space equals space cos to the power of negative 1 end exponent space open parentheses fraction numerator 4 over denominator 5 square root of 6 end fraction close parentheses
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78. Find the angle between the lines
straight x over 1 space equals fraction numerator negative straight y over denominator 0 end fraction space equals space fraction numerator straight z over denominator negative 1 end fraction space space and space space straight x over 3 space equals space straight y over 4 space equals straight z over 5

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 Multiple Choice QuestionsLong Answer Type

79. Find the value of p so that the lines
fraction numerator 1 minus straight x over denominator 3 end fraction space equals space fraction numerator 7 straight y minus 14 over denominator 2 space straight p end fraction space equals space fraction numerator straight z minus 3 over denominator 2 end fraction space space and space space fraction numerator 7 minus 7 straight z over denominator 3 space straight p end fraction space equals space fraction numerator straight y minus 5 over denominator 1 end fraction space equals space fraction numerator 6 minus straight z over denominator 5 end fraction
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 Multiple Choice QuestionsShort Answer Type

80. Show that the lines
fraction numerator straight x minus 5 over denominator 7 end fraction space equals space fraction numerator straight y plus 2 over denominator negative 5 end fraction space equals straight z over 1 space and space straight x over 1 space equals space straight y over 2 space equals space straight z over 3 are prependicular to each other. 
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