91.
Find the length of perpendicular from (2, 1, 3) on the line
Let the given line AB be
Any point M on this line is
(5 r + 4, 4 r + 2, 3 r + 3)
Let this point M be the foot of perpendicular from P(2, 1, 3) on AB.
Direction-ratios of PM are
5 r + 4 – 2, 4 r + 2 – 1, 3 r + 3 – 3 i.e. 5 r + 2, 4 r + 1, 3 r
Direction-ratios of AB are 5, 4, 3.
Since PM ⊥ AB
∴ (5 r – 2) (5) + (4 r + 1) (4) + (3 r) (3) = 0
∴ 25 r – 10 + 16 r + 4 + 9 r = 0
∴ required length of perpendicular = PM
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