Find the equation of the perpendicular drawn from the point (2,

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 Multiple Choice QuestionsShort Answer Type

91. Find the length of perpendicular from (2, 1, 3) on the line
fraction numerator straight x minus 4 over denominator 5 end fraction space equals fraction numerator straight y minus 2 over denominator 4 end fraction space equals space fraction numerator straight z minus 3 over denominator 3 end fraction.
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92.

Find the length and foot of the perpendicular drawn from the point (3, 4, 5) on the line 
fraction numerator straight x minus 2 over denominator 2 end fraction space equals space fraction numerator straight y minus 3 over denominator 5 end fraction space equals space fraction numerator straight z minus 1 over denominator 3 end fraction

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93.

Find the perpendicular distance of the point (1, 0, 0) form the line fraction numerator straight x minus 1 over denominator 2 end fraction space equals space fraction numerator straight y plus 1 over denominator negative 3 end fraction space equals space fraction numerator straight z plus 10 over denominator 8 end fraction

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94.

Find the length of the perpendicular drawn from the point (1, ,2 3) on the line
fraction numerator straight x minus 6 over denominator 3 end fraction space equals space fraction numerator straight y minus 7 over denominator 2 end fraction space equals space fraction numerator straight z minus 7 over denominator negative 2 end fraction

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95. Find the length and the foot of the perpendicular drawn from the point (2, – 1, 5) to the line fraction numerator straight x minus 11 over denominator 10 end fraction space equals space fraction numerator straight y plus 2 over denominator negative 4 end fraction space equals space fraction numerator straight z plus 8 over denominator negative 11 end fraction.
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 Multiple Choice QuestionsLong Answer Type

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96. Find the equation of the perpendicular drawn from the point (2, 4, – 1) to the line  fraction numerator straight x plus 5 over denominator 1 end fraction space equals space fraction numerator straight y plus 3 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator negative 9 end fraction.


Let the given line AB be
fraction numerator straight x plus 5 over denominator 1 end fraction space equals space fraction numerator straight y plus 3 over denominator 4 end fraction space equals space fraction numerator straight z minus 6 over denominator negative 9 end fraction
Any point M on line is (r – 5, 4 r – 3, – 9 r + 6)
Let this point M be the foot of perpendicular from P(2, 4, –1) on AB.

Direction ratios of PM are
r – 5 – 2, 4 r – 3 – 4, – 9 r + 6 + 1 i.e. r – 7, 4 r – 7, – 9 r + 7
Direction ratios of AB are 1, 4, – 9
Since PM ⊥ AB
∴  (1) (r – 7) + (4) (4 r – 7) + (– 9) (–9 r + 7) = 0
∴  r – 7 + 16 r – 28 + 81 r – 63 = 0
∴  98 r = 98 ⇒ r = 1
∴  Mis (1 – 5, 4 – 3, – 9 + 6) i.e. (– 4, 1, –3)
The equation of PM is
                              fraction numerator straight x minus 2 over denominator negative 4 minus 2 end fraction space equals space fraction numerator straight y minus 4 over denominator 1 minus 4 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 3 plus 1 end fraction

i.e.,                       fraction numerator straight x minus 2 over denominator negative 6 end fraction space equals space fraction numerator straight y minus 4 over denominator negative 3 end fraction space equals space fraction numerator straight z plus 1 over denominator negative 2 end fraction

i.e.,                         fraction numerator straight x minus 2 over denominator 6 end fraction space equals space fraction numerator straight y minus 4 over denominator 3 end fraction space equals space fraction numerator straight z plus 1 over denominator 2 end fraction

 
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97. Find the length of perpendicular from (3, 2, 1) on the line 
fraction numerator straight x minus 4 over denominator 5 end fraction space equals space fraction numerator straight y minus 2 over denominator 3 end fraction space equals space fraction numerator straight z minus 3 over denominator 4 end fraction

91 Views

 Multiple Choice QuestionsShort Answer Type

98. Find the coordinates of the foot of perpendicular drawn from the point A (1, 2, 1) to the line
fraction numerator straight x minus 1 over denominator 4 end fraction space equals space fraction numerator straight y minus 4 over denominator 0 end fraction space equals space fraction numerator straight z minus 6 over denominator negative 2 end fraction
99 Views

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 Multiple Choice QuestionsLong Answer Type

99. Find the image of the point (1, 6, 3) in the line straight x over 1 space equals space fraction numerator straight y minus 1 over denominator 2 end fraction space equals space fraction numerator straight z minus 2 over denominator 3 end fraction.
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 Multiple Choice QuestionsShort Answer Type

100. Find the area of the triangle whose vertices are (1, – 1, – 3), (4, – 3, 1), (3,– 1, 2).
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