Short Answer TypeFind equation of the plane parallel to x + 3y – 2z + 7 = 0 and passing through the origin.
Long Answer TypeShort Answer TypeIn each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
z = 2
The equation of plane is
z = 2 or 0x + 0y + 1.z = 2
It is of form lx + my + nz = p
where l = 0, m = 0, n = 1, p = 2
∴ direction cosines of the normal to the plane are 0, 0, 1 and distance from origin = 2.
In each of the following cases, determine the direction cosines of the normal to the plane and the distance from the origin.
x + y + z = 1
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