Find the vector and cartesian equations of the planes:that pass

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 Multiple Choice QuestionsShort Answer Type

181. Find the vector equation of the line through the origin which is perpendicular to the plane straight r with rightwards arrow on top. space open parentheses straight i with hat on top space minus space 2 space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 3.
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182. Find the vector and cartesian equations of the planes:
that passes through the point (1, 0, – 2) and the normal to the plane is straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top.


Here, stack straight r subscript 1 with rightwards arrow on top space equals straight i with hat on top space minus space 2 space straight j with hat on top comma space space space space space space straight n with rightwards arrow on top space equals space straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top
The vector equation of line is
                  left parenthesis stack straight r space with rightwards arrow on top space minus space stack straight r subscript 1 with rightwards arrow on top right parenthesis. space straight n with rightwards arrow on top space equals space 0
or     open square brackets straight r with rightwards arrow on top space minus space open parentheses straight i with hat on top space minus space 2 space straight k with hat on top close parentheses close square brackets. space left parenthesis straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top right parenthesis space equals space 0
Take straight r equals straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top
therefore space space space space open square brackets left parenthesis straight x space straight i with hat on top space plus space straight y space straight j with hat on top space plus space straight z space straight k with hat on top right parenthesis space minus space left parenthesis straight i with hat on top space minus space 2 space straight k with hat on top right parenthesis close square brackets. space space left parenthesis straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top right parenthesis space equals space 0
or       open square brackets open parentheses straight x minus 1 close parentheses space straight i with hat on top space plus space straight y space straight j with hat on top space plus space left parenthesis straight z plus 2 right parenthesis space straight k with hat on top close square brackets. space space left parenthesis straight i with hat on top space plus space straight j with hat on top space minus space straight k with hat on top right parenthesis space equals space 0
or       left parenthesis straight x minus 1 right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis straight y right parenthesis thin space left parenthesis 1 right parenthesis space plus space left parenthesis straight z plus 2 right parenthesis thin space left parenthesis negative 1 right parenthesis space equals space 0
or         straight x minus 1 plus straight y minus straight z minus 2 space equals space 0
or          straight x plus straight y minus straight z space equals space 3
which is cartesian equation of plane. 

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183. Find the vector and cartesian equations of the planes:
that passes through the point (1, 4, 6) and the normal vector to the plane is straight i with hat on top space minus space 2 space straight j with hat on top space plus space straight k with hat on top.
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 Multiple Choice QuestionsLong Answer Type

184. Find the vector equation of the line passing through the point (3, 1, 2) and perpendicular to the plane straight r with rightwards arrow on top. space open parentheses 2 straight i with hat on top space minus space straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 4. Find also the point of intersection of this line and plane. 
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 Multiple Choice QuestionsShort Answer Type

185. Find the angle between the two planes
3 x – 6 y + 2 z = 7 and 2 x + 2 y – 2 z = 5.
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186. Find the angle between the two planes
2 x + y – 2 z = 5 and 3x – 6 y – 2 z = 7 using vector method.
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187. Find the angle between the planes whose vector equations are
straight r with rightwards arrow on top. space open parentheses 2 straight i with hat on top space plus space 2 straight j with hat on top space minus space 3 straight k with hat on top close parentheses space equals space 5 space space space and space straight r with rightwards arrow on top. space open parentheses 3 straight i with hat on top space minus space 3 straight j with hat on top space plus space 5 straight k with hat on top close parentheses space equals space 3.
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188. Find the angle between the planes whose vector equations are
straight r with rightwards arrow on top. space open parentheses straight i with hat on top space plus space straight j with hat on top space minus space 2 space straight k with hat on top close parentheses space equals space 3 space space and space space space straight r with rightwards arrow on top. space space open parentheses 2 straight i with hat on top space minus space 2 straight j with hat on top space plus space straight k with hat on top close parentheses space equals space 2
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189. Find the angle between the planes
straight r with rightwards arrow on top. space open parentheses 3 space straight i with hat on top space minus space 4 space straight j with hat on top space plus space 5 space straight k with hat on top close parentheses space equals space 0 space space and space straight r with rightwards arrow on top. space space left parenthesis 2 straight i with hat on top space minus space straight j with hat on top space minus space 2 space straight k with hat on top right parenthesis space equals space 0

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190. In the following cases, determine whether the given planes are parallel or perpendicular, and in case they are neither, find the angles between them:
7x + 5y + 6z + 30 = 0 and 3x – y – 10z + 4 = 0

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